(t^2+4t+5)/(t+1)

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Solution for (t^2+4t+5)/(t+1) equation: 


D( t )

t+1 = 0

t+1 = 0

t+1 = 0

t+1 = 0 // - 1

t = -1

t in (-oo:-1) U (-1:+oo)

(t^2+4*t+5)/(t+1) = 0

t^2+4*t+5 = 0

t^2+4*t+5 = 0

DELTA = 4^2-(1*4*5)

DELTA = -4

DELTA < 0

1 = 0

1/(t+1) = 0

t belongs to the empty set

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